本帖最后由 zczczcle 于 2016-2-1 12:51 编辑 # e7 g' q/ a4 |' {: M
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首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。0 C3 N: U9 l+ I
其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。5 z2 i9 {. g4 D9 }# X# D# z
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。4 K9 \6 t! d3 m3 F
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部分选取代码,稍后解读:$ @8 o( J! d- l) ?+ d. g
WORD wNowTeamId = 0;# w b: ~: T5 O6 y
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_snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );
( M* Z( W5 N1 B Q/ D% K szFileName[256-1] = '\0';0 m$ x4 I" M1 ~
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() );
: B: G7 C7 H7 I+ u; p! q2 j szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';8 w0 ?) _" k5 \. T# b0 ?
strcat( szFileName, szMapLog );
* R& L8 \- e- u! L CInStream MonsterInfo( szFileName );
5 l+ O6 z" T, B0 B6 P' F# N4 P if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 )
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_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() ); ^2 e1 k( A# f& G; \
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';
3 x u/ R2 s9 P' p# B9 w AddMemoMsg(szMapLog);
# @, ]# ^( }3 s5 I return true;* B9 e( t O3 M7 T5 i) F
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( u# i" C3 ^ A* F" ifor( i = 0; i < iColNum; i++ )
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MonsterInfo >> dwTeamId
/ u* H' c! [- [6 v7 Q, G I >> dwMonsterId
( w5 h$ \+ t9 T5 [( \ >> dwX
4 s m( s% }( F2 w6 Y9 M >> dwY
9 O, D. C" e/ r$ h+ ~# B8 H0 l6 S >> dwCount;
, Y8 W+ c# q0 ~ }& D if( wNowTeamId < dwTeamId )
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5 }) K9 G C9 O wNowTeamId = dwTeamId;- o. n+ _$ [1 N* ?+ |
}
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for( j = 0; j < dwCount; j++ )
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5 V1 H' @4 p8 l if( pBaseMonster->GetSpeed() )
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for( int z = 0; z < 10; z++ )
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, b6 H$ P) ]5 ?/ @, q' K dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );5 D. c' e2 L1 E. ^# n/ N0 Q) z
dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );0 T% F* [/ Y6 N2 I! ?
if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;
* O8 A6 w: U$ \ else if( z == 9 ). n8 m3 Q. u2 r9 l: `, ]
{
, W( h6 [' F7 T& p5 ]3 T/ x1 p& i dwRandX = -1 + gf_GetRandom( 2 );
/ R' l7 n3 H1 o# p dwRandY = -1 + gf_GetRandom( 2 );3 x# G" w9 D# k" T. \1 G- p$ X4 ~
}
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else
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) a4 `( H1 |9 _ l3 @& X dwRandX = dwRandY = 0;( h( s8 Y' \. T0 @
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所以我的初步结论是:3 p4 R5 B/ r6 G0 N+ l7 t: {
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