本帖最后由 zczczcle 于 2016-2-1 12:51 编辑
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首先,这并不能预测下一个boss具体刷在哪,不过你能通过我的解读知道,boss是怎么个刷法。
/ ?' [# n, ~1 Q# J2 p. p其次,如果你有挂(付费的每天更新的那种),或者自己会解封包的话,你就能知道附近是否出现小boss了,在附近的话你还能知道他的位置。" s5 _4 G4 v1 q
kuqitt 这位大哥提到打开MonsterList文件第一个数字是0是乱刷,但是后来又不确定很疑惑,原因就在于那个0,1,2,3,4和乱刷与否并无关系,或许是凑巧。) j% o! _7 ?/ a y" c' |/ b
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部分选取代码,稍后解读:: m8 O; y+ L: T+ E& r% m
WORD wNowTeamId = 0;
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3 ]& A, a6 v2 z2 N6 n& u5 k _snprintf( szFileName, 256-1, "%s//Monster//MonsterList",g_pBase->GetObjectFilePath() );/ P+ J6 _: d3 Y1 w w
szFileName[256-1] = '\0';5 K3 `" A: x; p9 U3 ~9 d
_snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "_%d.txt", (int)m_pBase->GetMapId() ); 2 q6 b9 |7 `: G0 A: u W9 t; O% k
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';+ P- x: B& G6 {/ ~' |
strcat( szFileName, szMapLog );
8 g& O' o" o5 q- \% b CInStream MonsterInfo( szFileName );
/ Y' H/ ?" w( D) |; _4 `' A if ( MonsterInfo.fail() || MonsterInfo.GetFileSize() == 0 )
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( d! e: s* ]1 r0 ]- e& V3 F; B2 R: P _snprintf( szMapLog, MAX_MEMO_MSG_LEN-1, "***** The Map(%d) Have No Monsters ! *****", GetMapId() ); l% ^" x( b; F% [8 q& a( G
szMapLog[MAX_MEMO_MSG_LEN-1] = '\0';' \, e8 m1 N8 G/ b: V1 V
AddMemoMsg(szMapLog);
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for( i = 0; i < iColNum; i++ )
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MonsterInfo >> dwTeamId 8 {7 Z( P' X B% H
>> dwMonsterId
- j# g8 F: M5 P9 u/ Q >> dwX ! ^ J; i8 O, B; [$ G/ a
>> dwY
+ t% [4 X/ b( d5 Y0 k# Z# L >> dwCount;" G$ C3 ~7 T2 A" o- Q- t
if( wNowTeamId < dwTeamId )
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, O4 q9 S: }9 J+ ?3 X, d/ |% U wNowTeamId = dwTeamId;; j# \/ P7 Q! t( J2 k
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( C1 A, K% s8 C& x/ v for( j = 0; j < dwCount; j++ )
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6 q% e; ^5 E' v; b4 G, C if( pBaseMonster->GetSpeed() )2 ]" @- G/ {% M% K
{
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dwRandX = gf_GetRandom( 14 ) - gf_GetRandom( 14 );% K6 d5 a' g \; q9 W. n
dwRandY = gf_GetRandom( 14 ) - gf_GetRandom( 14 );
$ J. m& x3 U& k1 f( | @5 z if( !( GetTileFlag( dwX + dwRandX, dwY + dwRandY ) & TILE_ALLOCCULDE ) ) break;
! x- V# }/ ?/ A6 x7 p else if( z == 9 )* i6 ~2 B% b3 Z# b6 v4 Q- v
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dwRandX = -1 + gf_GetRandom( 2 );0 r \3 P5 Y$ @
dwRandY = -1 + gf_GetRandom( 2 );4 `! d5 }! A. m+ @( t" m
}
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dwRandX = dwRandY = 0;5 W) U: U# l; \" u
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5 _0 d6 ]: i5 K& I3 T6 d所以我的初步结论是:' v/ ~) A1 T% J5 z
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